`int(x+1)/(sqrt(x-1))dx`

If int (x+1)/(sqrt(2x-1))dx = f(x)sqrt(2x-1)+C , where C is a constant of integration, then f(x) is equal to

Evaluate: int(x+1)/(sqrt(2x-1))\ dx

The value of int(1)/(x+sqrt(x-1))dx , is

Evaluate: int(x-1)/sqrt (x^2-1)dx

Evaluate the following integral: int_1^5x/(sqrt(2x-1))dx

Evaluate: int1/((x+1)sqrt(x^2-1))dx

Evaluate: int1/((x+1)sqrt(x^2-1))dx

Evaluate: int1/((x+1)sqrt(x^2-1))dx

Evaluate: int(x-1)/(sqrt(x^2+1))\ dx

Evaluate: int(x+1)/(sqrt(x^2+1))\ dx