If `veca.vecb = 0` then

l veca . m vecb = lm(veca . vecb) and veca . vecb = 0 then veca and vecb are perpendicular if veca and vecb are not null vector

If vecasxxvecb=0 and veca.vecb=0 then (A) veca_|_vecb (B) veca||vecb (C) veca=0 and vecb=0 (D) veca=0 or vecb=0

If |veca|=2 and |vecb|=3 and veca.vecb=0, " then " (vecaxx(vecaxx(vecaxx(vecaxxvecb)))) is equal

STATEMENT-1 Let veca,vecb bo two vectors such that veca.vecb=0 , then veca and vecb are perpendicular. And STATEMENT-2 Two non-zero vectors are perpendicular if and only if their dot product is zero.

If |veca|=and |vecb|=3 and veca.vecb=0 ,then (veca(vecx(vecaxx(vecaxx))))= (A) 48hatb (B) -48hatb (C) 48hata (D) -48hata

If three vectors vecA, vecB and vecC satisfy the relation vecA.vecB = 0 & vecA.vecC = 0 then the vector vecA is parallel to vecB xx vecC . Statement-2 : vecA _|_vecB and vecA_|_vecC hence A is perpendicular to plane formed by vecB and vecC .

If veca=0 or vecb=0 then vecaxxvecb=0 . Is then converse true? Justify your answer with and example

If veca.vecb=0 and vecaxxvecb=0 prove that veca=0 or vecb=vec0 .

If veca, vecb, vecc are vectors such that veca.vecb=0 and veca + vecb = vecc then: