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If 5g of steam at 100^(@)C is mixed with...

If 5g of steam at `100^(@)C` is mixed with 5g of ice at `0^(@)C` ,then the resultant temperature of the mixture is (`L_(V)=540cal` /g ,`L_(f)=80cal`/g `C_(W)=1cal` /`g^(@)C)]`
1) `77^(@)C`
2) `127^(@)C`,
3) `55^(@)C`
4) `100^(@)C`

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