A van is moving with a speed of `72 km h^(−1)` on a level road, where the coefficient of friction between its tyres and road is `0.5`. The minimum radius of curvature, the road must have for safe driving of van is `(g = 10 ms^(−2))`.

The coefficient of friction between the tyres and road is 0.4. The minimum distance covered before attaining a speed of 8 ms^(-1) starting from rest is nearly ( take g=10 ms^(-2) )

The coefficient of friction between the tyres and the road is 0.1. The maximum speed with which a cyclist can take a circular turn of radius 3 m without skidding is ("Take g"=10ms^(-2))

What is the minimum stopping distance for a vehicle of mass m moving with speed v along a level road. If the coefficient of friction between the tyres and the road is mu .

What will be maximum speed of a car on a curved road of radius 30 m , If the coefficient of friction between the tyres and the road is 0.4? (g=9.8 m//s^(2))

What will be the maximum speed of a car on a road turn of radius 30 m, if the coefficient of friction between the tyres and the road is 0.4? (Take g=9.8m//s^(2) )

The mass of a bicycle rider along with the bicycle is 100 kg. he wants to cross over a circular turn of radius 100 m with a speed of 10 ms^(-1) . If the coefficient of friction between the tyres and the road is 0.6, will the rider be able to cross the turn? Take g = 10 ms^(-2) .

A car has to move on a level turn of radius 45 m. If the coefficient of static friction between the tyre and the road is mu_s=2.0, find the maximum speed the car can take without skidding.

If a cyclist moving with a speed of 4.9 m/s on a level can take a sharp circular turn of radius 4 m, then coefficient between the cycle tyres and road is

A car is moving along a straight horizontal road with a speed v_(0) . If the coefficient of friction between the tyres and the road is mu , the shortest distance in which the car can be stopped is

A car is moving on a horizontal circular road of radius 0.1 km with constant speed. If coefficient of friction between tyres of car and road is 0.4, then speed of car may be (g=10m//s^(2))