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(dy)/(dx)=(2xy)/(x^(2)-y^(2))...

`(dy)/(dx)=(2xy)/(x^(2)-y^(2))`

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STATEMENT -1 : The differential equation (dy)/(dx) = (2xy)/(x^(2) + y^(2)) Can't be solved by the substitution x = vy. and STATEMENT-2 : When the differential equation is homogeneous of first order and first degree, then the substitution that solves the equation is y = vx.

(dy)/(dx) = (2xy)/(x^(2)-1-2y)

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If the straight line y=x meets y=f(x) at P, where f(x) is a solution of the differential equation (dy)/(dx)=(x^(2)+xy)/(x^(2)+y^(2)) such that f(1)=3 , then the value of f'(x) at the point P is

The differential equations of all circle touching the x-axis at orgin is (a) (y^(2)-x^(2))=2xy((dy)/(dx)) (b) (x^(2)-y^(2))(dy)/(dx)=2xy ( c ) (x^(2)-y^(2))=2xy((dy)/(dx)) (d) None of these

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On putting (y)/(x)=v the differential equation (dy)/(dx)=(2xy-y^(2))/(2xy-x^(2)) is transferred to

Solve the following differential equations (dy)/(dx)=(x^(2)+y^(2))/(x^(2)+xy)