A charge Q is given to a solid conducting sphere of mass "m' and is rotating about it's diameter with angular velocity `w`.Then ratio of it's magnetic moment to its angular momentum is

The ratio of magnetic dipole moment to angular momentum of electron is

A thin uniform ring of radius R carrying charge q and mass m rotates about its axis with angular velocity omega . Find the ratio of its magnetic moment and angular momentum.

Solid uniform conductiong sphere of mass 'm' and charge Q , rotates about its axis of symmetry with constant angular velocity 'omega' then the ratio of magnetic moment to the moment of inertia of the sphere is (xQomega)/(6m) then x is :(Neglect induced charges due to centrifugal force)

When an electron revolves around the nucleus, then the ratio of magnetic moment to angular momentum is

A thin disc of radius R has charge Q distributed uniformly on its surface. The disc is rotated about one of its diametric axis with angular velocity omega . The magnetic moment of the arrangement is

A thin disc of radius R and mass M has charge q uniformly distributed on it. It rotates with angular velocity omega . The ratio of magnetic moment and angular momentum for the disc is

A particle of charge q and mass m moves in a circular orbit of radius r with angular speed w the ratio of the magnitude of its magnetic moment to that of its angular momentum depends on

A particle of charge 'q' and mass 'm' move in a circular orbit of radius 'r' with frequency 'v' the ratio of the magnetic moment to angular momentum is:

A solid cylinder of mass M and radius R rotates about its axis with angular speed omega . Its rotational kinetic energy is

Angular momentum of a rigid body rotating about a fixed Axis with angular velocity vec omega