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Evaluate : ( veca times veca ) . vecb...

Evaluate :
`( veca times veca ) . vecb`

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If veca and vecb are two vectors, such that |veca xx vecb|=2 , then find the value of [veca vecb veca xx vecb]

If veca and vecb are two vectors, such that |veca xx vecb|=2 , then find the value of [veca vecb veca xx vecb]

If [ veca vecbvecc]=2 , then find the value of [(veca+2vecb-vecc) (veca - vecb) (veca - vecb-vecc)]

If [ veca vecbvecc]=2 , then find the value of [(veca+2vecb-vecc) (veca - vecb) (veca - vecb-vecc)]

If veca, vecb, vecc are unit vectors such that veca. Vecb =0 = veca.vecc and the angle between vecb and vecc is pi/3 , then find the value of |veca xx vecb -veca xx vecc|

Show that (veca xx vecb)^(2) = |veca| ^(2) |vecb|^(2) - (veca.vecb)^(2) = |(veca.veca)/(veca. vecb)(veca.vecb)/(vecb.vecb)|

If the vectors veca and vecb are mutually perpendicular, then veca xx {veca xx {veca xx {veca xx vecb}} is equal to:

If veca, vecb and vecc are vectors such that veca. vecb = veca.vecc, veca xx vecb = veca xx vecc, a ne 0. then show that vecb = vecc.

Let veca vecb and vecc be three non-zero vectors such that veca + vecb + vecc = vec0 and lambda vecb xx veca xx veca + vecbxxvecc + vecc + veca = vec0 then find the value of lambda .

given that veca. vecb = veca.vecc, veca xx vecb= veca xx vecc and veca is not a zero vector. Show that vecb=vecc .