`y^2dx + (xy+x^2)dy`=0

y dx+(x-y^2)dy=0

Show that y^(2)dx + (xy + x^(2))dy = 0 is a homogeneous differential equation. Also find its general solution.

y^2dx+(x^2-xy+y^2)dy=0

Solve: y^2dx+(x^2+xy+y^2)dy=0

Solve: x^2dy-y^2dx+xy^2(x-y)dy=0

Equation of curve passing through (1,1) & satisfyng the differential equation (xy^(2)+y^(2)+x^(2)y+2xy)dx+(2xy+x^(2))dy=0 is

The solution of the differential equation y(xy + 2x^2y^2) dx + x(xy-x^2y^2)dy = 0 is given by

The solution of y^2dx+(x^2-xy+y^2)dy=0 is (A) y=Ce^(tan^-1x) (B) y=Ce^(tan^-1y) (C) y=Ce^(tan^-1(y/x)) (D) y=C[tan^-1(y/x)+e^(x^2)+y^2]

(y^2e^x+2xy)dx-x^2dy=0

Solve the following differential equation: (3xy + y^(2)dx) + (x^(2) + xy)dy = 0