Evaluate `(x-ab)/(a+b)+(x-bc)/(b+c)+(x-ca)/(c+a)=a+b+c`

Solve the equation, (x - ab)/(a + b) + (x - bc)/(b + c) + (x - ca)/(c + a)= a + b + c . What happens if 1/(a + b) + 1/( b + c) + 1/(c + a) = 0

If a^(2) +b^(2) +c^(2) = ab + bc + ca then ((a+b)/(c ) + (b+c)/(a) + (c+a)/(b)) ((c )/(a+b) + (b)/(a+c) + (c )/(a+b)) =?

If ab + bc + ca = 0, then find the value of (b)/((a+b)(b+c))+(c)/((a+c)(c+b))+(a)/((a+b)(c+a))

If a,b,c are in AP, show that (a(b+c))/(bc) , (b (c+a))/(ca), (c(a+b))/(ab) , are also in AP.

If a^(2) +b^(2) +c^(2) = ab + bc + ca then (a+b)/(c ) + (b+c)/(a) + (c+a)/(b) =?

If a^(2) +b^(2) +c^(2) = ab + bc + ca then (c )/(a+b) + (b)/(a +c)+ (c )/(a+b) = ?

For any positive real number x;write the value of {(x^(a))^(b)}^((1)/(ab)){(x^(b))^(c)}^((1)/(bc)){(x^(c))^(a)}^((1)/(ca))