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A 5% (w/V) solution of cane sugar (molec...

A 5% (w/V) solution of cane sugar (molecular mass =342 ) is isotonic with 1% (w/V) 0.1 molal aqueous solution of an electrolyte `AB_(3)` is 90% ionized.The boiling point (in Kelvin scale) of the solution at 1 atm is : `(K_(b(H_(2)O))`=0.52K `kg mol ^(-1) )`

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0.1 molal aqueous solution of an electrolyte AB_(3) is 90% ionised. The boiling point of the solution at 1 atm is ( K_(b(H_(2)O)) = 0.52 kg " mol"^(-1) )

1.0 molal aqueous solution of an electrolyte "A"_(2)"B"_(3) is 60% ionised. The boiling point of the solution at 1 atm is ("K"_("b"("H"_(2)"O"))=0.52 "K kg mol"^(-1)")

1 molal aqueous solution of an electrolyte AB_(2) is 80% ionized into A^(+2) and B^(-1) ions . The boiling point of the solution at 1 atm is : [K_(b) (H_(2)O) = 0.5 kg mol^(-1) ]

2.0 molal aqueous solution of an electrolyte X_(2) Y_(3) is 75% ionised. The boiling point of the solution a 1 atm is ( K_(b(H_(2)O)) = 0.52K kg mol^(-1) )

3.0 molal aqueous solution of an electrolyte A_(2)B_(3) is 50% ionised. The boilng point of the solution at 1 atm is: [k_(b) (H_2O) = 0.52 K kg mol^(-1)]

A 5% (w/V ) solution of cane sugar (molecular mass = 342) is isotonic with 1% (w/V) solution of a subtance X. The molecular mass of X is :

1.0 molal aqueous solution of an electrolyte X_(3)Y_(2) is 25% ionized. The boiling point of the solution is (K_(b) for H_(2)O = 0.52 K kg//mol) :

1.0 molal aqueous solution of an electrolyte X_(3)Y_(2) is 25% ionised . The boiling point of the solution is : ( K_(b) for H_(2)O = 0.52K kg/mol)