`cot(A-B)=(cot A cot B+1)/(cot B-cot A)`

Prove that: (cos A+cos B)/(cos B-cos A)=cot((A+B)/2)cot((A-B)/2)

simplify (1)/(cosec A-cot A)+(1)/(cosec A+cot A)=?

In Delta ABC, "cot"(A)/(2) + "cot" (B)/(2) + "cot" (C)/(2) is equal to

Prove that : (cot A + tan B)/ (cot B + tan A) = cot A tan B

If cos(A+B)sin(C+D)=cos(A-B)sin(C-D) , prove that cot A cot B cot C=cotD .

Solution set of inequality (cot^-1x)^2-5cot^-1x+6>0 is (A) (cot 3 , cot2) (B) (-oo, cot3) uu (cot2 , oo) (C) (cot2, oo) (D) None of these

If A and B are complementary angles, prove that : cot A cot B - sin A cos B - cos A sin B = 0

Prove that: cot x cot 2x - cot 2x cot 3x - cot 3x cot x = 1

In a triangle ABC if cot(A/2)cot(B/2)=c, cot(B/2)cot(C/2)=a and cot(C/2)cot(A/2)=b then 1/(s-a)+1/(s-b)+1/(s-c)=

If A+B+C=pi , prove that : cot, A/2+ cot, B/2 + cot, C/2 = cot, A/2 cot, B/2 cot, C/2