I=int(1)/(1-(3x)^(2))dx...

`I=int(1)/(1-(3x)^(2))dx`

I=int(1)/(1-(3x)^(2))dx
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int(1)/(2-3x)+(1)/(sqrt(3x-2))dx
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int1/(2-3x)+1/(sqrt(3x-2))\ dx
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Evaluate : (i) int(2x)/((2x+1)^(2))dx (ii) int((2+3x))/((3-2x))dx
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int(x^2)/((x-1)(3x-1)(3x-2))dx=
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int(1)/((3x+2)^(1/3))dx
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int(1)/((3x+2)^(1/3))dx
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int(1)/((3x+2)^(1/3))dx
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I=int(1)/(3x^(2)+6)dx
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