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An object of height 3.0 cm is placed ver...

An object of height 3.0 cm is placed vertically on the principal axis of a convex lens. When the object distance is - 37 .5 cm. an image of height - 2.0 cm is formed at a distance of 25.0 cm form the lens . Next the same object is place vertically at 25.0 cm from the lens . In this situation the image distance v and height h of the image is (according to the new Cartesian sign convention )

A

v = + 37.5 cm, h = + 4.5

B

v = - 37 . 5 cm, h = + 4.5 cm

C

v = + 37 . 5 cm, h = - 4.5 cm

D

v = - 37 . 5 cm, h = - 4.5 cm

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