Area intercepted by the curves `y=cos x`,`x in[0,pi]` and `y=cos2x`,`x in[0,pi]` is

The area bounded by the curve y=cosx and y=sin 2x, AA x in [(pi)/(6), (pi)/(2)] is equal to

The area enclosed by the curve |y|=sin2x, where x in [0,2pi]. is

The area bounded by the curve y = sin x , x in [0,2pi] and the x -axis is equal to:

The area bounded by the curve y = cos^-1(cos x) and y=|x-pi| is

Draw the graph of y = sin x + cos x, x in [0, 2pi].

The ratio of the areas between the curves y=cos x and y=cos 2x and x-axis from x=0 to x=pi/3 is

Find the area bounded by the curve y = cos x between x = 0 and x=2pi .

Area of the regionbounded by the curve y = "cos" x between x = 0 and x = pi is

The area of the closed figure bounded by the curves y=cosx,y =1+(2)/(pi)x and x=pi//2, is

The angle of intersection of the curves y=2\ sin^2x and y=cos2\ x at x=pi/6 is (a) pi//4 (b) pi//2 (c) pi//3 (d) pi//6