`tan^(-1)(3/5)+tan^(-1)(4/5)=?`

Prove that : tan^(-1)(1/2) + tan^(-1)(1/3) = tan^(-1)(3/5) + tan^(-1)(1/4) = pi/4

prove tan^(-1)(3/5)+tan^(-1)(1/4)=(pi)/(4)

Prove that tan^(-1)(3/5)+tan^(-1)(1/4)=(pi)/(4)

tan^(-1) (1/5) + tan^(-1) (1/7) + tan^(-1) (1/3) + tan^(-1) (1/8) = π/4

Prove that tan^ (-1)( 1/3) +tan^(-1)( 1/5) + tan^(-1) (1/7 )+tan^(-1) (1/8) = pi/4

Prove that tan ^(-1)(1/5) + tan^(-1)(1/7) +tan^(-1)(1/3)+ tan ^(-1)(1/8) = pi/4

The angle between the normals of ellipse 4x^2 + y^2 = 5 , at the intersection of 2x+y=3 and the ellipse is (A) tan^(-1) (3/5) (B) tan^(-1) (3/4) (C) tan^(-1) (4/3) (D) tan^(-1) (4/5)

Prove that tan^(-1) (1/8) +tan^(-1) (1/5) =tan^(-1) (1/3)

tan^(-1)((3)/(4))+tan^(-1)((3)/(5))-tan^(-1)((8)/(19))=