The image of `(2,3)` with respect to `y` axis is collinear with `(-1,-1)` and `(-4,lambda)` then `lambda`=
` (A) `-11`
(B)`12`
(C) `11`
(D)`-12`

If |vec(a) | = 4 and -3 le lamda le 2 ,then I lambda veca I lies in (A) [0,12] (B) [2,3] (C) [8,12] (D) [-12,8]

If I vec(a) I = 4 and -3 le lamda le 2 ,then I lambda vec(a) I lies in (A) [0,12] (B) [2,3] (C) [8,12] (D) [-12,8]

If A =[(2,-1),(-1,2)] and B=[(1,4),(-1,1)] then find (A+B)^2

If the points (a,b),(1,1)and (2,2) are collinear then

If 2x+y+lambda=0 is a normal to the parabola y^2=-8x , then lambda is (a)12 (b) -12 (c) 24 (d) -24

A plane pi makes intercepts 3 and 4 respectively on z-axis and x-axis. If pi is parallel to y-axis, then its equation is (A) 3x-4z=12 (B) 3x+4z=12 (C) 3y+4z=12 (D) 3z+4y=12

Image of (1, 2, 3) w.r.t a plane is (-7/3,-4/3,-1/3) then which of the following points lie on the plane (A) (-1,1,-1) (B) (-1,-1,1) (C) (-1,-1,1) (D) (1,1,-1)

Find the value of lambda . If the points A(-1,3,2), B(-4,2,-2) and C(5,lambda,10) are collinear.

If the points A(-1,3,2),B(-4,2,-2)a n dC(5,5,lambda) are collinear, find the value of lambda .

If the points A(lambda, 2lambda), B(3lambda,3lambda) and C(3,1) are collinear, then lambda=