Let `f:(3,6)rarr(4,7)` be a function defined by `f(x)=(4x)/(3)-{(x)/(3)}` (where `{}` denotes the fractional part function) then `f^(-1)(x)` is equal to

Let f:(6, 8)rarr (9, 11) be a function defined as f(x)=x+[(x)/(2)] (where [.] denotes the greatest integer function), then f^(-1)(x) is equal to

Let f : [2, 4) rarr [1, 3) be a function defined by f(x) = x - [(x)/(2)] (where [.] denotes the greatest integer function). Then f^(-1) equals

Let f:(4,6)vec(6,8) be a function defined by f(x)=x+[x/2]dotw h e r e[dot] denotes the greatest integer function, then f^(-1)(x) is equal to (A) x-2 (B) x-[x//2] (C) -x-2 (D) none of these

Period of the function f(x)=sin(sin(pix))+e^({3x}) , where {.} denotes the fractional part of x is

Period of the function f(x) = cos(cospix) +e^({4x}) , where {.} denotes the fractional part of x, is

Let f:R rarr R be a function defined as f(x)=(x^(2)-6)/(x^(2)+2) , then f is

Let f:(1,3) to R be a function defined by f(x)=(x[x])/(1+x) , where [x] denotes the greatest integer le x . Then the range of f is :

The range of the function f(x) = frac{1-{x}}{1+{x}} is (where {.} denotes the fractional part of x )

Let f:(-oo,2] to (-oo,4] be a function defined by f(x)=4x-x^(2) . Then, f^(-1)(x) is

Let f:(2,4)->(1,3) where f(x) = x-[x/2] (where [.] denotes the greatest integer function).Then f^-1 (x) is