Simplify :

`( tanA - 1/(tanA )) /( tanB - 1/( tanB ) )`

tanA +tanB + tanC = tanA tanB tanC if

Prove that: (tanA + tanB)/(cotA+cotB)=tanAtanB

If A+B=225^(@) , then (tanA)/(1-tanA).(tanB)/(1-tanB)=?

If A+B=315^@ then (1-tanA)(1-tanB)=

If, in a triangleABC , tanA =1 and tanB=2, then: tanC=

(cot A+tanB)/(cotB+tanA) is :

If p=(secA - tanA) (secB - tanB) (secC - tanC) = (secA + tanA) (secB + tanB)(secC + tanC) , then value of p is:

If A+B+C= pi/2 , show that : tanA tanB + tanB tanC + tanC tanA=1

If A-B = pi/4 , then (1+tanA)(1-tanB)=