Simplify :

`( tanA - tanB ) /( 1 + tanAtanB )`

tanA +tanB + tanC = tanA tanB tanC if

Prove that: (tanA + tanB)/(cotA+cotB)=tanAtanB

If sinA=(3)/(5)andcosB=(12)/(13) ,what is the value of (tanA-tanB)/(1+tanAtanB) ,it being given that A and B are acute angles ?

If A=60^(@) and B=30^(@) , verify that : (i)sin(A-B)=sinAcosB-cosAsinB (ii) cos(A-B)=cosAcosB+sinAsinB (iii) tan(A-B)=(tanA-tanB)/(1+tanAtanB)

If sinA=1/sqrt2, cosB=sqrt3/2 then (tanA+tanB)/(1-tanAtanB)=

If A and B are supplementary angles then find the value of (tanA+tanB)/(1-tanAtanB)

If cosA=(3)/(5) and sinB=(5)/(13) , find the value of (tanA+tanB)/(1-tanAtanB) :

Prove that- sin(A-B)/sin(A+B)= (tanA-tanB)/(tanA+tanB)

Prove that- sin(A-B)/sin(A+B)= (tanA-tanB)/(tanA+tanB)

In any triangle ABC , (tanA/2-tanB/2)/(tanA/2+tanB/2) is equal to