lim_(x→1)⁡ [log⁡x/(x−1)]

Evaluate : lim_(x rarr1) (logx /(x - 1))

Evalaute lim_(xto1) (1+logx-x)/(1-2x+x^(2))

If 0ltlog_(e)xltsqrt(x) for all xlt1, then find the value of lim_(xtooo) (log_(e)x)/(x).

Evaluate: (lim)_(x->e)(logx-1)/(x-e)

lim_(x→0) (√(x+1)−1)/x

The value of lim_(xrarre) (logx-1)/(x-e) , is

lim_(xrarre) (log_(e)x-1)/(|x-e|) is

STATEMENT-1 : lim_(x->oo)(log[x])/([x])=0 . STATEMENT-2 : lim_(x->0)(sqrt(sec^2-1))/x does not exist. STATEMENT-3: lim_(x->2)(x-1)^(1/(x-2)) = 1

The value of lim_(xrarr1) (logx)/(sin pi x) , is

lim_(x->1) (log_3 3x)^(log_x 3)=