If a body is released from a point at a height equal to n times the radius of the earth its velocity on reaching the surface of the earth is (R is radius of earth)

The escape velocity from the surface of the earth is (where R_(E) is the radius of the earth )

A man weighs 'W' on the surface of the earth and his weight at a height 'R' from surface of the earth is ( R is Radius of the earth )

The escape velocity of a body from the surface of the earth is equal to

What is the maximum height attained by a body projected with a velocity equal to one- third of the escape velocity from the surface of the earth? (Radius of the earth=R)

A body is released from a point of distance R' from the centre of earth. Its velocity at the time of striking the earth will be (R’gtR_(e))

A body attains a height equal to the radius of the earth. The velocity of the body with which it was projected is

A body is projected up with a velocity equal to 3//4th of the escape velocity from the surface of the earth. The height it reaches is (Radius of the earth is R )

A ball A of mass m falls on the surface of the earth from infinity. Another ball B of mass 2m falls on the earth from the height equal to six times the radius of the earth. Then ratio of velocities of A and B on reaching the earth is sqrt(x//y) where x and y are coprimes. Find x+y .

The ratio of acceleration due to gravity at a height 3 R above earth's surface to the acceleration due to gravity on the surface of earth is (R = radius of earth)

A particle is throws vertically upwards from the surface of earth and it reaches to a maximum height equal to the radius of earth. The radio of the velocity of projection to the escape velocity on the surface of earth is