A capacitor of capacitance `1muF` has initial charge `10muC`.Now it is connected to a source of voltage `20V`.The charge in steady state of the capacitor is:

A capacitor of capacitance C carrying charge Q is connected to a source of emf E . Finally, the charge on capacitor would be

The charge on the capacitor in steady state in the circuit shown is

A capacitor gets a charge of 60muC when it is connected to a battery of emf 12 V. Calculate the capacitance of the capactor.

The circuit is in a steady state. The charge in capacitor C_1 is

The circuit is in a steady state. The charge in capacitor C_2 is

One plate of a capacitor of capacitance 2muF has total charge +10muC and its other plate has total charge +40muC . The potential difference between the plates is (in Volt).

A capacitor of 8 F is connected as shown in the figure. At steady state Charge on the plates of the capacitor

A parallel plate capacitor A is filled with a dielectric whose dielectric constant varies with applied voltage as K = V. An identical capacitor B of capacitance C_0 with air as dielectric is connected to voltage source V_0 = 30V and then connected to the first capacitor after disconnecting the voltage source. The charge and voltage on capacitor.

Find the charge on capacitor in steady state.

A capacitor of capacitance C is initially charged to a potential difference of V volt. Now it is connected to a battery of 2V with oppoiste polarity. The ratio of heat generated to the final enegry stored in the capacitor will be