Shortest distance between the lines `(x)/(-3)=(y-1)/(1)=(z+1)/(-1)` and `x-2=y-3=-z-(13)/(7)` is

Statement 1: The shortest distance between the lines x/(-3)=(y-1)/1=(z+1)/(-1)a n d(x-2)/1=(y-3)/2=((z+(13//7))/(-1)) is zero. Statement 2: The given lines are perpendicular.

The shortest distance between the lines x/(-3)=(y-1)/1=(z+1)/(-1)a n d(x-2)/1=(y-3)/2=((z+(13//7))/(-1)) is zero. Statement 2: The given lines are perpendicular.

Find the magnitude of the shortest distance between the lines (x)/(2)=(y)/(-3)=(z)/(1) and (x-2)/(3)=(y-1)/(-5)=(z+2)/(2) .

If the shortest distance between the lines (x-3)/(3)=(y-8)/(-1)=(z-3)/(1) and (x+3)/(-3)=(y+7)/(2)=(z-6)/(4) is lambdasqrt(30) unit, then the value of lambda is

Shortest distance between the lines (x-1)/1=(y-1)/1=(z-1)/1a n d(x-2)/1=(y-3)/1=(z-4)/1 is equal to

Find the shortest distance between the lines (x+2)/(-4) = (y)/(1) = (z-7)/(1) and (x+3)/(-4) = (y-6)/(3) = 9/2

Shortest distance between the lines (x-1)/1=(y-1)/1=(z-1)/1a n d(x-2)/1=(y-3)/1=(z-4)/1 is equal to a. sqrt(14) b. sqrt(7) c. sqrt(2) d. none of these

The direction ratios of the line of shortest distance between the lines (x-2)/1=(y-3)/4=(z+1)/3 and (x-3)/2=(y-4)/3=(z-1)/2

The shortest distance between the lines (x-3)/3=(y-8)/(-1)=(z-3)/1 and (x+3)/(-3)=(y+7)/2=(z-6)/4 is

Find the length of the shortest distance between the lines (x-1)/2=(y-4)/3=(z+1)/(-3) and (x-4)/1=(y-3)/3=(z-2)/2