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In the following questions, two equation...

In the following questions, two equations numbered I and II are given. You have to solve both the equations and
Give answer If
`x^2-3x-40=0`
`y^2-15y+54=0`

A

`xgty`

B

`xley`

C

`xgey`

D

x=y or the relationship cannot be established

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given equations step by step, we will first solve each equation separately. ### Step 1: Solve the first equation \( x^2 - 3x - 40 = 0 \) 1. **Identify the equation**: We have \( x^2 - 3x - 40 = 0 \). 2. **Factor the quadratic equation**: We need to find two numbers that multiply to \(-40\) (the constant term) and add up to \(-3\) (the coefficient of \(x\)). - The numbers are \(-8\) and \(5\) because \(-8 \times 5 = -40\) and \(-8 + 5 = -3\). 3. **Rewrite the equation**: We can factor the equation as: \[ (x - 8)(x + 5) = 0 \] 4. **Set each factor to zero**: - \(x - 8 = 0 \Rightarrow x = 8\) - \(x + 5 = 0 \Rightarrow x = -5\) So, the solutions for \(x\) are \(x = 8\) and \(x = -5\). ### Step 2: Solve the second equation \( y^2 - 15y + 54 = 0 \) 1. **Identify the equation**: We have \( y^2 - 15y + 54 = 0 \). 2. **Factor the quadratic equation**: We need to find two numbers that multiply to \(54\) (the constant term) and add up to \(-15\) (the coefficient of \(y\)). - The numbers are \(-9\) and \(-6\) because \(-9 \times -6 = 54\) and \(-9 + -6 = -15\). 3. **Rewrite the equation**: We can factor the equation as: \[ (y - 9)(y - 6) = 0 \] 4. **Set each factor to zero**: - \(y - 9 = 0 \Rightarrow y = 9\) - \(y - 6 = 0 \Rightarrow y = 6\) So, the solutions for \(y\) are \(y = 9\) and \(y = 6\). ### Step 3: Compare the values of \(x\) and \(y\) We have the following pairs of solutions: 1. \(x = -5\) and \(y = 6\) → Here, \(x < y\) 2. \(x = -5\) and \(y = 9\) → Here, \(x < y\) 3. \(x = 8\) and \(y = 6\) → Here, \(x > y\) 4. \(x = 8\) and \(y = 9\) → Here, \(x < y\) From the comparisons, we can conclude: - In two cases, \(x\) is less than \(y\). - In one case, \(x\) is greater than \(y\). Since there is no consistent relationship established between \(x\) and \(y\) across all cases, we conclude that the relationship cannot be established definitively. ### Final Answer: The correct answer is option 4: The relationship cannot be established. ---
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