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A and B started a business. B’s investme...

A and B started a business. B’s investment was ₹4000 more than that of A. At the end of 8 months from the start of the business, B left and C joined with an investment which was ₹6000 more than that of A. If the ratio of the total annual profit to B’s share in profit was 11:5, then what was the investment made by A?

A

₹ 6000

B

₹ 12000

C

₹ 8000

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will denote A's investment as \( X \). ### Step 1: Define Investments - A's investment = \( X \) - B's investment = \( X + 4000 \) (since B's investment is ₹4000 more than A's) - C's investment = \( X + 6000 \) (since C's investment is ₹6000 more than A's) ### Step 2: Determine Time of Investment - A invests for 12 months. - B invests for 8 months (he leaves after 8 months). - C invests for 4 months (he joins when B leaves). ### Step 3: Calculate Total Investment Contributions - A's total contribution = \( 12X \) - B's total contribution = \( (X + 4000) \times 8 = 8X + 32000 \) - C's total contribution = \( (X + 6000) \times 4 = 4X + 24000 \) ### Step 4: Total Investment The total investment can be expressed as: \[ \text{Total Investment} = 12X + (8X + 32000) + (4X + 24000) \] Combining the terms: \[ \text{Total Investment} = 12X + 8X + 4X + 32000 + 24000 = 24X + 56000 \] ### Step 5: Profit Sharing Ratio Given that the ratio of total annual profit to B's share in profit is \( 11:5 \), we can denote: - Total profit = \( 11Y \) - B's share in profit = \( 5Y \) ### Step 6: Relate B's Profit to Investment Since profit is directly proportional to investment: \[ B's \, share = \frac{B's \, investment}{Total \, investment} \times Total \, profit \] This gives us: \[ 5Y = \frac{(8X + 32000)}{(24X + 56000)} \times 11Y \] Cancelling \( Y \) from both sides (assuming \( Y \neq 0 \)): \[ 5 = \frac{(8X + 32000) \times 11}{(24X + 56000)} \] ### Step 7: Cross Multiply Cross multiplying gives: \[ 5(24X + 56000) = 11(8X + 32000) \] Expanding both sides: \[ 120X + 280000 = 88X + 352000 \] ### Step 8: Rearranging the Equation Rearranging gives: \[ 120X - 88X = 352000 - 280000 \] \[ 32X = 72000 \] ### Step 9: Solve for X Dividing both sides by 32: \[ X = \frac{72000}{32} = 2250 \] ### Conclusion Thus, the investment made by A is ₹2250.
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