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What will come in place of question mark...

What will come in place of question mark (?) in the given questions?
`(36-:sqrt18xxsqrt6)-:3=?`

A

`6sqrt3`

B

`6sqrt2`

C

`4sqrt3`

D

`4/sqrt2`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \( (36 \div \sqrt{18} \times \sqrt{6}) \div 3 = ? \), we will follow the order of operations (BODMAS/BIDMAS). ### Step-by-Step Solution: 1. **Identify the Expression**: The expression we need to solve is: \[ (36 \div \sqrt{18} \times \sqrt{6}) \div 3 \] 2. **Calculate the Square Roots**: We first need to simplify \( \sqrt{18} \) and \( \sqrt{6} \): \[ \sqrt{18} = \sqrt{9 \times 2} = 3\sqrt{2} \] \[ \sqrt{6} = \sqrt{6} \] 3. **Substitute Back into the Expression**: Now substitute the square roots back into the expression: \[ (36 \div (3\sqrt{2}) \times \sqrt{6}) \div 3 \] 4. **Simplify Inside the Bracket**: First, calculate \( 36 \div (3\sqrt{2}) \): \[ 36 \div (3\sqrt{2}) = \frac{36}{3\sqrt{2}} = \frac{12}{\sqrt{2}} \] 5. **Multiply by \( \sqrt{6} \)**: Now multiply this result by \( \sqrt{6} \): \[ \frac{12}{\sqrt{2}} \times \sqrt{6} = \frac{12\sqrt{6}}{\sqrt{2}} = 12 \times \sqrt{\frac{6}{2}} = 12 \times \sqrt{3} = 12\sqrt{3} \] 6. **Divide by 3**: Now divide by 3: \[ \frac{12\sqrt{3}}{3} = 4\sqrt{3} \] 7. **Final Answer**: Therefore, the value that comes in place of the question mark (?) is: \[ 4\sqrt{3} \]
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