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If x=alpha"cos^3 theta and y = alpha sin...

If `x=alpha"cos^3 theta` and `y = alpha sin^3 theta`, then `1+((dy)/(dx))^2` is equal to :

A

`"tan" theta`

B

`"tan"^2 theta`

C

1

D

`sec^2 theta`

Text Solution

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The correct Answer is:
D
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