The corner points of the feasible region determined by the following system of linear inequalities:
`2x+yge10, x+3yle15,x,yge0` are `(0,0),(5,0),(3,4)` and `(0,5)`. Let `Z=px+qy`, where `p,qge0`. Condition on `p` and `q` so that the maximum of `Z` occurs at both `(3,4)` and `(0,5)` is:
(a) `p=q` (b) `p=2q` (c) `p=eq` (d) `q=3p`

Options

A. p=q
B. p=2q
C. p=3q
D. q=3p

Answer

D