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If A and B are any 2xx2 matrices, then d...

If A and B are any `2xx2` matrices, then det (A+B)=0 implies:

A

det A=0 and det B=0

B

det A+det `B!=0`

C

det A=0 or det B=0

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the implications of the determinant of the sum of two 2x2 matrices being zero. Let's denote the matrices as \( A \) and \( B \). ### Step-by-Step Solution: 1. **Understanding the Determinant Condition**: We are given that \( \text{det}(A + B) = 0 \). This means that the matrix \( A + B \) is singular, i.e., it does not have an inverse. 2. **Exploring the Properties of Determinants**: The determinant of a sum of matrices does not have a straightforward relationship with the determinants of the individual matrices. However, we can explore specific cases to understand the implications. 3. **Choosing Specific Matrices**: Let's consider two specific matrices: \[ A = \begin{pmatrix} 1 & 0 \\ 1 & 0 \end{pmatrix}, \quad B = \begin{pmatrix} -1 & 0 \\ 0 & -1 \end{pmatrix} \] Now, we compute \( A + B \): \[ A + B = \begin{pmatrix} 1 & 0 \\ 1 & 0 \end{pmatrix} + \begin{pmatrix} -1 & 0 \\ 0 & -1 \end{pmatrix} = \begin{pmatrix} 0 & 0 \\ 1 & -1 \end{pmatrix} \] 4. **Calculating the Determinant of \( A + B \)**: Now, we calculate the determinant: \[ \text{det}(A + B) = \text{det}\begin{pmatrix} 0 & 0 \\ 1 & -1 \end{pmatrix} = (0)(-1) - (0)(1) = 0 \] This confirms that \( \text{det}(A + B) = 0 \). 5. **Calculating the Determinants of \( A \) and \( B \)**: Next, we calculate the determinants of \( A \) and \( B \): \[ \text{det}(A) = (1)(0) - (0)(1) = 0 \] \[ \text{det}(B) = (-1)(-1) - (0)(0) = 1 \] 6. **Analyzing the Options**: Now we analyze the options given in the question: - **Option 1**: \( \text{det}(A) = 0 \) and \( \text{det}(B) = 0 \) (False, since \( \text{det}(B) = 1 \)) - **Option 2**: \( \text{det}(A) + \text{det}(B) \neq 0 \) (True, since \( 0 + 1 \neq 0 \)) - **Option 3**: \( \text{det}(A) = 0 \) or \( \text{det}(B) = 0 \) (True, since \( \text{det}(A) = 0 \)) - **Option 4**: None of these (False, since Option 2 and Option 3 are true) 7. **Conclusion**: The correct implication of \( \text{det}(A + B) = 0 \) is that at least one of the matrices \( A \) or \( B \) must be singular (i.e., have a determinant of zero). Thus, the correct answer is that \( \text{det}(A) = 0 \) or \( \text{det}(B) = 0 \). ### Final Answer: The correct implication is that \( \text{det}(A) = 0 \) or \( \text{det}(B) = 0 \).
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