Given that A=[(alpha, beta),(gamma, alph...

Given that `A=[(alpha, beta),(gamma, alpha)] and A^(2) =3I`, then :

A

`1+alpha^2+betagamma=0`

B

`1-alpha^2+betagamma=0`

C

`3-alpha^2-betagamma=0`

D

`3 +alpha^2+betagamma=0`

Text Solution

Verified by Experts

The correct Answer is:

C

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