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If the circumference of a circle is eqau...

If the circumference of a circle is eqaul to the perimeter of a square, then what will be the ratio of their areas ? (Where `pi=22/7`)

A

`14 : 11`

B

`21 : 1`

C

`11 : 4`

D

`5 : 7`

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The correct Answer is:
To solve the problem of finding the ratio of the areas of a circle and a square when their circumference and perimeter are equal, we can follow these steps: ### Step 1: Define the formulas - The circumference \( C \) of a circle is given by the formula: \[ C = 2\pi r \] where \( r \) is the radius of the circle. - The perimeter \( P \) of a square with side length \( a \) is given by: \[ P = 4a \] ### Step 2: Set the circumference equal to the perimeter Since the circumference of the circle is equal to the perimeter of the square, we can set the two equations equal to each other: \[ 2\pi r = 4a \] ### Step 3: Solve for the radius \( r \) To find \( r \), we can rearrange the equation: \[ r = \frac{4a}{2\pi} = \frac{2a}{\pi} \] ### Step 4: Find the area of the circle The area \( A_c \) of the circle is given by: \[ A_c = \pi r^2 \] Substituting the value of \( r \): \[ A_c = \pi \left(\frac{2a}{\pi}\right)^2 = \pi \cdot \frac{4a^2}{\pi^2} = \frac{4a^2}{\pi} \] ### Step 5: Find the area of the square The area \( A_s \) of the square is given by: \[ A_s = a^2 \] ### Step 6: Find the ratio of the areas Now, we can find the ratio of the area of the circle to the area of the square: \[ \text{Ratio} = \frac{A_c}{A_s} = \frac{\frac{4a^2}{\pi}}{a^2} = \frac{4}{\pi} \] ### Step 7: Substitute the value of \( \pi \) Given \( \pi = \frac{22}{7} \), we substitute this value into the ratio: \[ \text{Ratio} = \frac{4}{\frac{22}{7}} = 4 \times \frac{7}{22} = \frac{28}{22} = \frac{14}{11} \] ### Final Answer Thus, the ratio of the areas of the circle to the square is: \[ \boxed{\frac{14}{11}} \]
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