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The ratio of the HCF and LCM of 52 and 1...

The ratio of the HCF and LCM of 52 and 130 is:

A

`1 : 10`

B

`10 : 1`

C

`2 : 5`

D

`5 : 2`

Text Solution

AI Generated Solution

The correct Answer is:
To find the ratio of the HCF (Highest Common Factor) and LCM (Lowest Common Multiple) of the numbers 52 and 130, we will follow these steps: ### Step 1: Find the prime factorization of both numbers. - **For 52**: - 52 can be divided by 2: \( 52 \div 2 = 26 \) - 26 can be divided by 2: \( 26 \div 2 = 13 \) - 13 is a prime number. - Therefore, the prime factorization of 52 is \( 2^2 \times 13^1 \). - **For 130**: - 130 can be divided by 2: \( 130 \div 2 = 65 \) - 65 can be divided by 5: \( 65 \div 5 = 13 \) - 13 is a prime number. - Therefore, the prime factorization of 130 is \( 2^1 \times 5^1 \times 13^1 \). ### Step 2: Find the HCF (Highest Common Factor). - The HCF is found by taking the lowest power of all common prime factors. - Common prime factors of 52 and 130 are: - \( 2 \) (minimum power is \( 1 \)) - \( 13 \) (minimum power is \( 1 \)) Thus, the HCF is: \[ HCF = 2^1 \times 13^1 = 2 \times 13 = 26 \] ### Step 3: Find the LCM (Lowest Common Multiple). - The LCM is found by taking the highest power of all prime factors present in either number. - Prime factors are: - \( 2 \) (maximum power is \( 2 \)) - \( 5 \) (maximum power is \( 1 \)) - \( 13 \) (maximum power is \( 1 \)) Thus, the LCM is: \[ LCM = 2^2 \times 5^1 \times 13^1 = 4 \times 5 \times 13 \] Calculating this: \[ 4 \times 5 = 20 \] \[ 20 \times 13 = 260 \] So, the LCM is \( 260 \). ### Step 4: Find the ratio of HCF to LCM. Now we can find the ratio: \[ \text{Ratio} = \frac{HCF}{LCM} = \frac{26}{260} \] Simplifying this: \[ \frac{26}{260} = \frac{1}{10} \] ### Final Answer: The ratio of the HCF and LCM of 52 and 130 is \( \frac{1}{10} \). ---
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