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When degree measure of angle centre is t...

When degree measure of angle centre is `theta`, then what will be area of sector:

A

`sqrt(3a)` cm

B

`theta/180^@xxpir`

C

`theta/360^@xxpir^2`

D

`theta/180^@xx2pir`

Text Solution

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The correct Answer is:
To find the area of a sector of a circle when the degree measure of the angle at the center is given as \( \theta \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Circle and Sector**: - We have a circle with a center \( C \) and a radius \( r \). - The angle at the center of the circle is \( \theta \) degrees. 2. **Area of the Circle**: - The area \( A \) of the entire circle is given by the formula: \[ A = \pi r^2 \] 3. **Proportion of the Circle**: - The full circle corresponds to an angle of \( 360^\circ \). - Therefore, the area of the circle that corresponds to \( 360^\circ \) is \( \pi r^2 \). 4. **Area per Degree**: - To find the area covered by \( 1^\circ \), we can divide the total area by \( 360 \): \[ \text{Area per degree} = \frac{\pi r^2}{360} \] 5. **Area of the Sector**: - For an angle of \( \theta \) degrees, the area of the sector \( A_{\text{sector}} \) can be calculated by multiplying the area per degree by \( \theta \): \[ A_{\text{sector}} = \theta \times \frac{\pi r^2}{360} \] 6. **Final Formula**: - Thus, the area of the sector is given by: \[ A_{\text{sector}} = \frac{\theta}{360} \times \pi r^2 \] ### Final Result: The area of the sector when the degree measure of the angle at the center is \( \theta \) is: \[ A_{\text{sector}} = \frac{\theta}{360} \pi r^2 \]
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