What are the zeroes of the polynomial `(x^2-9 )`?

Options

A. (3, 0)
B. (3, -3)
C. (0, 3)
D. (3, 3)

Answer

To find the zeroes of the polynomial \( x^2 - 9 \), we need to determine the values of \( x \) for which the polynomial equals zero.

### Step-by-Step Solution:

1. **Set the polynomial equal to zero:**
\[ x^2 - 9 = 0 \]

2. **Rearrange the equation:**
\[ x^2 = 9 \]

3. **Take the square root of both sides:**
\[ x = \pm \sqrt{9} \]

4. **Calculate the square root:**
\[ x = \pm 3 \]

5. **Write the zeroes:**
The zeroes of the polynomial \( x^2 - 9 \) are:
\[ x = 3 \quad \text{and} \quad x = -3 \]

### Final Answer:
The zeroes of the polynomial \( x^2 - 9 \) are \( 3 \) and \( -3 \).