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A boy walks 12 m due east and 5 m due so...

A boy walks 12 m due east and 5 m due south. How far is he from the starting point?

A

12 M

B

17 M

C

13 M

D

20 M

Text Solution

AI Generated Solution

The correct Answer is:
To find out how far the boy is from the starting point after walking 12 m due east and then 5 m due south, we can use the Pythagorean theorem. Here’s the step-by-step solution: ### Step 1: Understand the movement The boy walks: - 12 m due east (let's call this distance AB) - 5 m due south (let's call this distance BC) ### Step 2: Visualize the path We can visualize the boy's path as a right triangle: - Point A is the starting point. - Point B is where he ends up after walking east. - Point C is where he ends up after walking south. ### Step 3: Identify the sides of the triangle In this right triangle: - AB = 12 m (the horizontal leg) - BC = 5 m (the vertical leg) - AC is the hypotenuse, which represents the distance from the starting point A to the final point C. ### Step 4: Apply the Pythagorean theorem According to the Pythagorean theorem: \[ AC^2 = AB^2 + BC^2 \] Substituting the known values: \[ AC^2 = 12^2 + 5^2 \] ### Step 5: Calculate the squares Calculating the squares: \[ 12^2 = 144 \] \[ 5^2 = 25 \] ### Step 6: Add the squares Now, add these values: \[ AC^2 = 144 + 25 = 169 \] ### Step 7: Find the square root To find AC, we take the square root of both sides: \[ AC = \sqrt{169} = 13 \] ### Conclusion The distance from the starting point to the final point is **13 meters**. ---
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