Find `dy/dx` where `x=a(cos t+t sin t),y=a(sin t-t cos t)`

Find dy/dx x=e^t (sin t + cos t ),y=e^t(sin t -cos t)

If x=a (cos t + t sin t) and y=a ( sin t- t cos t), find (d^(2)y)/(dx^(2))

Find (dy)/(dx) , when x=a\ cos^3t and y=at .

x=a(cos t + log tan (t/2)), y =a sin t

If x=a(cos t+t sin t) and y=a(sin t - t cos t), then (d^2y)/dx^2

Find (dy)/(dx) , when x=a t^2 and y=2\ a t

Locus of centroid of the triangle whose vertices are (a cos t, a sin t ) , (b sin t - b cos t ) and (1, 0) where t is a parameter, is

' find dy/dx if x=3sin t-2 sin ^3t, y=3 cos t -2cos^3t

x=a cos t, y=b sin t find dy/dx

x=a (t-sin t) , y =a (1-cos t) find dy/dx