`|[3x-8,3,3],[3,3x-8,3],[3,3,3x-8]|=0` then, `x=?`

One root of the equation |(3x-8, 3, 3),(3,3x-8, 3),(3,3,3x-8)|=0 si (A) 8/3 (B) 2/3 (C) 1/3 (D) 16/3

One root of the equation |(3x-8, 3, 3),(3,3x-8, 3),(3,3,3x-8)|=0 is (A) 8/3 (B) 2/3 (C) 1/3 (D) 16/3

Solve : |[x-2,2x-3,3x], [-4x-4,2x-9,3x-16], [x-8,2x-27,3x-64]| = 0

If x in N and |[x+3,-2],[-3x,2x]|=8, then find the value of x

Solve for x |x-2 , 2x-3, 3x-4,x-4 ,2x-9, 3x-16 ,x-8, 2x-27, 3x-64|=0.

If (7+4sqrt(3))^(x^(2-8))+(7-4sqrt(3))^(x^(2-8))=14, then x=

Solve x^(3)-8x-3=0 .

If (-2,\ 1) is the centroid of the triangle having its vertices at (x ,\ 0),\ (5,\ -2),\ (-8,\ y), then x ,\ y satisfy the relation 3x+8y=0 (b) 3x-8y=0 (c) 8x+3y=0 (d) 8x=3y

If "log"_(x+2) (x^(3)-3x^(2)-6x +8) =3 , then x equals to