The intercept of plots of log V vs log T curves at constant P for 1 mole of an ideal gas will be

Draw the plot log V vs log T.

For V versus T curves at constant pressure P_1 and P_2 for and ideal gas shown in figure-

In a plot of log k vs 1/T, the slope is

The intercept on y-axis and slope of curve plotted between P/T vs. T ( For an ideal gas having 10 moles in a closed rigid container of volume 8.21 L. (P= Pressure in atm and T = Temp. in K, log_(10)2=0.30)) are respectively :

The plot og log k vs 1//T helps to calculate

Draw the plot log P vs log V for Boyle's law.

Which of the plots of ln K vs (1/T) is/are correct?

When a sample of ideal gas is changed from an initial state to a final state, various curves can be plotted for the process like P-V curve, V-T curve,P-T curve etc. For example, P-V curve for a fixed amount of an ideal gas at constant temperature is a rectangular hyperbola, V-T curve for a fixed amount of an ideal gas at constant volume is again a straight line. However, the shapes may vary if the constant parameters are also changed. Now, answer the following questions : Two moles of an ideal gas is changed from its initial state (16 atm, 6L) to final state (4 atm, 15L) in such a way that this change can be represented by a straight line in P-V curve.The maximum temperature attained by the gas during the above change is :(Take : R=1/12L atm K^(-1) "mol"^(-1) )