number of `d` electrons in `cr^(+3)`

The orbital configuration of ._(24)Cr is 3d^(5) 4s^(1) . The number of unpaired electrons in Cr^(3+) (g) is

Calculate the value of ((x+y^(2)))/2 for Cr^(3+) ion. where x= number of unpaired electron in Cr^(3+) and y= spin only magnetic moment of Cr^(3+)

the number of d- electrons in Mn^(2+) is equal to that of :

The number of d electrons in Fe^(2+) (atomic number of Fe = 26 ) is equal to

The number of d electrons in Fe^(2+) (atomic number of Fe = 26 ) is not equal to that of the.

The number of d-electrons in [Cr(H_(2)O)_(6)]^(3+) [atomic number of Cr =24] is :

The number of unpaired electron in Cr^(+2) is

Predict the number of unpaired electrons in [Cr(CN)_6]^(4-)

Predict the number of unpaired electrons in [Cr(H_2O)_6]^(2+)

Write doen the number of 3d electrons in each of the following ions: Ti^(2+),V^(2+),Cr^(3+),Mn^(2+),Fe^(2+),Fe^(2+),Co^(2+),Ni^(2+) and Cu^(2+) indicate how would you expect the five 3d orbitals to be occupied for these hydrated ions (octahedral).