In absence of dielectric medium ,capacity of a parellel plate capacior os c0 A sheet of dielectric constant K and thickness of one third of the plate is inserted betweeen the plates ,if new capacity is C then

Find an expression for the capacitance of a parallel plate capacitor when a dielectric slab of dielectric constant K and thickness t=(d)/(2) but the same area on the plates is inserted between the the capacitors plate. (d=separation between the plates)

Separation between the plates of a parallel plate capacitor is d and the area of each plates is A . When a slab of material of dielectric constant k and thickness t(t lt d) is introduced between the plates. Its capacitance becomes

The potential enery of a charged parallel plate capacitor is U_(0) . If a slab of dielectric constant K is inserted between the plates, then the new potential energy will be

The potential enery of a charged parallel plate capacitor is U_(0) . If a slab of dielectric constant K is inserted between the plates, then the new potential energy will be

The capacitance of a parallel plate condenser is C_(0) If a dielectric of relative permittivity epsilon_(r) and thickness equal to one fourth the plate separation is placed between the plates, then its capacity becomes C. The value of (C)/(C_(0)) will be -

Find the capacitance between A and B if two dielectric alabs (each of area A ) of dielectric constants K_(1) and K_(2) and thicknesses d_(1) and d_(2) are inserted between the plates of a parallel plate capacitor of plate area A . .

Half of the space between the plates of a parallel plate capacitor is filled with dielectric material of constant K. Then which of the plots are possible?

A battery charges a parallel plate capacitor of thickness (d) so that an energy [U_(0)] is stored in the system. A slab of dielectric constant (K) and thickness (d) is then introduced between the plates of the capacitor. The new energy of the system is given by

A paller- plate capacitor has plate area 100cm^2 and plate separation 1.0cm.A glass plate (dielectric constant 4.0)are inserted one over the other the fill the space between the plate of the capacitor.Find the new capacitance.

A parallel plate capacitor with air as the dielectric has capacitance C. A slab of dielectric constant K and having the same thickness as the separation between plates is introduced so as to fill one-fourth of the capacitor as shown in the figure. The new capacitance will be :