When a block of mass 5kg is suspended by a long wire of length 1m, the length of wire becomes 2.001 m,then elastic potential energy stored in the stretched wire is (`g = 10m/s^2`)

When a block of mass M is suspended by a long wire of length L, the length of the wire becomes (L+l). The elastic potential energy stored in the extended wire is

Elastic Potential Energy Stored In A Stretched Wire

A block of mass M is suspended from a wire of length L, area of cross-section A and Young's modulus Y. The elastic potential energy stored in the wire is

Derive an expression for the elastic potential energy stored in a stretched wire under stress.

When a block of mass M is suspended by a long wire of length L, the elastic potential energy stored in the wire is 1/2xxstressxxstrainxxvolume. Show that it is equal to 1/2Mgl where 1 is the extension. The loss in gravitational potential energy of the mass earth system is Mgl. Where does the remaining 1/2Mgl energy go ?

When a 1.0kg mass hangs attached to a spring of length 50 cm, the spring stretches by 2 cm. The mass is pulled down until the length of the spring becomes 60 cm. What is the amount of elastic energy stored in the spring in this condition. if g = 10 m//s^(2).

When a load of 10 kg is suspended on a metallic wire, its length increase by 2 mm. The force constant of the wire is

A wire suspended vertically from one of its ends is stretched by attaching a weight of 100 N to its lower end. What is the elastic potential energy stored in the wire, if the weight stretches the wire by 1.5 mm ?

A wire 2 m in length suspended vertically stretches by. 10 mm when mass of 10 kg is attached to the lower end. The elastic potential energy gain by the wire is (take g = 10 m//s^(2) )