In an equilateral triangle,`R:r:r1` is equal to

In an equilateral triangle with usual notations the value of (27r^(2)R)/(r_(1)r_(2)r_(3)) is equal to

In an equilateral triangle, the inradius and the circumradius are connected by r=4R b. r=R//2 c. r=R//3 d. none of these

In an equilateral triangle show that the in-radius and the circum-radius are connected by r =R/2.

A B C is an equilateral triangle of side 4c mdot If R ,r and h are the circumradius, inradius, and altitude, respectively, then (R+r)/h is equal to

A B C is an equilateral triangle of side 4c mdot If R , r, a n d,h are the circumradius, inradius, and altitude, respectively, then (R+r)/h is equal to (a) 4 (b) 2 (c) 1 (d) 3

From a uniform disc of radius R, an equilateral triangle of side sqrt(3)R is cut as shown in the figure. The new position of centre of mass is :

Assertion (A): z_1,z_2 and origin form an equilateral triangle if p^2=6q for the equation z^2 + pz+q=0 , Reason (R): Triangle having vertices z_1,z_2,z_3 in the Argand plane is equilateral if z_1^2+z_2^2+z_3^2=z_1z_2+z_2z_3+z3z_1 (A) Both A and R are true and R is the correct explanation of A (B) Both A and R are true R is not te correct explanation of A (C) A is true but R is false. (D) A is false but R is true.

In Figure, P Q R S is a square and S R T is an equilateral triangle. Prove that P T=Q T (ii) /_T Q R=15^0

In triangleABC , if R/r le 2 , and a=2, then triangle is equal to (triangle=ar(triangleABC)) .

In triangle ABC, let angle C = pi//2 . If r is the inradius and R is circumradius of the triangle, then 2(r + R) is equal to