If `f'(2^(+))=0` and `f'(2^(-))=0` then is `f(x)` continous at x=2?

If f(0) = f'(0) = 0 and f''(x) = tan^(2)x then f(x) is

if f(x)=e^(-1/x^2),x!=0 and f (0)=0 then f'(0) is

If f'(x)=(dx)/((1+x^(2))^(3//2)) and f(0)=0. then f(1) is equal to

If f'(x)=(1)/((1+x^(2))^(3//2)) and f(0)=0, then f(1) is equal to :

Let f(x)=(sin x)/(x), x ne 0 . Then f(x) can be continous at x=0, if

Let f(x)= {(((xsinx+2cos2x)/(2))^((1)/(x^(2))),,,,xne0),(e^(-K//2),,,,x=0):} if f(x) is continous at x=0 then the value of k is (a) 1 (b) 2 (c) 3 (d) 4

If f^(prime)(x)=3x^2-2/(x^3) and f(1)=0 , find f(x) .

Let f(x) be a polynomial function: f(x)=x^(5)+ . . . . if f(1)=0 and f(2)=0, then f(x) is divisible by

Suppose |(f'(x),f(x)),(f''(x),f'(x))|=0 where f(x) is continuously differentiable function with f'(x)ne0 and satisfies f(0) = 1 and f'(0) = 2 then lim_(xrarr0) (f(x)-1)/(x) is

If f(x)=x-2, x le 0 and 4-x^2,x > 0, then discuss the continuity of y=f(f(x)).