If focus is `(-1,2)` ,directrix is `17y=4` and length of latus rectum is `(18)/(5)` then eccentricity of that conic,is

If the distance between the foci of an ellipse is 8 and length of latus rectum is 18/5, then the eccentricity of ellipse is:

If the focus of a parabola is (3,3) and its directrix is 3x-4y=2 then the length of its latus rectum is

Find the vertex, focus, directrix and length of the latus rectum of the parabola y^2 - 4y-2x-8=0

Find the equation of the ellipse whose focus is S(-1, 1), the corresponding directrix is x -y+3=0, and eccentricity is 1/2. Also find its center, the second focus, the equation of the second directrix, and the length of latus rectum.

Find the eccentricity, coordinates of the foci, equations of directrices and length of the latus rectum of the hyperbola 3x^2-y^2=4

Find the foci, vertices, eccentricity and length of latus rectum of the hyperbola : y^2/4 - x^2/9 = 1 .

Find the latus rectum and eccentricity of the ellipse whose semi-axes are 5 and 4.

Find the foci, vertices, eccentricity and length of latus rectum of the hyperbola : 3y^2 - x^2 = 27 .

Find the centre, focus, eccentricity and length of latus rectum of the hyperbola 16x^(2)-9y^(2)=144 .

Find the value of lambda if the equation (x-1)^2+(y-2)^2=lambda(x+y+3)^2 represents a parabola. Also, find its focus, the equation of its directrix, the equation of its axis, the coordinates of its vertex, the equation of its latus rectum, the length of the latus rectum, and the extremities of the latus rectum.