If velocity (V), acceleration (A), and force (F) are taken as fundamental quantities instead of mass (M), length (L), and time (T) , the dimension of young's modulus (Y) would be

If the velocity (V) , acceleration (A) , and force (F) are taken as fundamental quantities instead of mass (M) , length (L) , and time (T) , the dimensions of young's modulus (Y) would be

If density (D), acceleration (a) and force (F) are taken as basic quantities, then Time period has dimensions

Time (T), velocity (C) and angular momentum (h) are chosen as fundamental quantities instead of mass, length and time. In terms of these, the dimensions of mass would be:

Time (T), velocity (C) and angular momentum (h) are chosen as fundamental quantities instead of mass, length and time. In terms of these, the dimensions of mass would be

Time (T), velocity (C) and angular momentum (h) are chosen as fundamental quantities instead of mass, length and time. In terms of these, the dimensions of mass would be

If force, acceleration and time are taken as fundamental quantities, then the dimensions of length will be:

If instead of mass, length and time as fundamental quantities we choose velocity, acceleration and force as fundamental quantities and express their dimesional symbols as v, a and F respectively. Show that the dimensions of Young's modulus can be expressed as Fa^(2)v^(-4)

If force (F) , velocity (V) and time (T) are taken as fundamental units, then the dimensions of mass are

If force (F) , velocity (V) and time (T) are taken as fundamental units, then the dimensions of mass are

If the energy ( E) ,velocity (v) and force (F) be taken as fundamental quantities,then the dimension of mass will be