Graph of the function `f(x)=|x-2|` is

1.The slope of the normal at the point with abscissa x=-2 of the graph of the function f(x)=|x^(2)-x| is

Draw the graph of the function: f(x)=||x-2|-3|

The sum of all the integral values of a {where a in(-10,10)} such that the graph of the function f(x)=||x-2|-a|-3 has exastly three x-intercepts is

Draw the graph of the function f(x)=x-|x-x^(2)|,-1<=x<=1 and discuss the continuity or discontinuity of f in the interval -1<=x<=1

Draw the graph of the function f(x)=2x-|x|

Draw the graph of the function: f(x)=log|x|

Mark the graph of the function f(x) = |{x}|

Mark the graph of the function f(x) = [|x|]

Draw the graph of the function: f(x)=|x^(2)-3|x|+2|

Draw the graph of the function: f(x)=-|x-1|^((1)/(2))