`dy/dx=e^x(sinx+cosx)`

Solve: (d^2y)/dx^2=e^x(sinx+cosx) , given that y=1 and (dy)/(dx)=0 , when x=0

ysinx dy/dx=(sinx-y^2)cosx

Find dy/dx for the function: f(x)=e^x(sinx-cosx) .

If y=e^x(sinx+cosx) prove that (d^2y)/(dx^2)-2(dy)/(dx)+2y=0 .

Verify that the function defined by y = sinx - cosx is a solution of the initial value problem dy / dx = sinx +cosx ; such that y(0) = -1

int e^x(sinx+cosx)dx=

find dy/dx if y= sinx.cosx

Find dy/dx if y= sinx^cosx .

Find dy/dx if y= sinx/cosx

Find dy/dx if y= sinx.cosx