An electrochemical cell has two half cell reactions as `A^(2+)+2e^(-)rarr A;E^(0)=0.63V`
`X rarr X^(2+)+2e^(-);E^(0)=2.37V` The cell voltage will be

An electrochemical cell has two half cell reaction as, A^(2+)+2e^-toA,E^0=0.34V XtoX^(2+)+2e^-,E^0=+2.37V . The cell voltage will be

The standard potential E^(@) for the half reactions are as : Zn rarr Zn^(2+) + 2e^(-), E^(@) = 0.76V Cu rarr Cu^(2+) +2e^(-) , E^(@) = -0.34 V The standard cell voltage for the cell reaction is ? Zn +Cu^(2) rarr Zn ^(2+) +Cu

Which has maximum potential for the half-cell reaction? 2H^(+) + 2e^(-) rarr H_(2)

The standard reductino potentials E^(c-) for the half reactinos are as follows : ZnrarrZn^(2+)+2e^(-)" "E^(c-)=+0.76V FerarrFe^(2+)+2e^(-) " "E^(c-)=0.41V The EMF for the cell reaction Fe^(2+)+Znrarr Zn^(2+)+Fe is

The standard electrode potentials of the two half cells are given below: Ni^(2+)+2e rarr Ni(s),E^(o) = - 0.25V, Zn^(2+) + 2e rarr Zn(s) , E^(o) = - 0.77 V. The voltage of the final cell formed by combining the two half cells would be:

The voltage of a cell whose half-cells are given below is Mg^(2+)+2e^(-)rarrMg(s),E^(@)=-2.37V Cu^(2+)+2e^(-)rarrCu(s),E^(@)=+0.34V standard EMF of the cell is

The standard electrode potential of the half cells are given below : Zn^(2+)+ 2e^(-) rarr Zn(s), E^(o) = - 7.62 V Fe^(2+) + 2e^(-) rarr Fe(s) , E^(o) = -7 .81 V The emf of the cell Fe^(2+) + Zn rarr Zn^(2+) + Fe will be :

Reduction potential for the following half-cell reaction are Zn rarr Zn^(2+)+2e^(-),E_(Zn^(2+)//Zn)^(@) = -0.76V Fe rarr Fe^(2+)+2e^(-),E_(Fe^(2+)//Fe)^(@) = -0.44V The emf for the cell reaction Fe^(2+) + Zn rarr Zn^(2+)+Fe will be

Standard oxidation potential for the following half-cell reactions are [Fe(s) rarr Fe^(2+)(aq) + 2e^(-) E^3 = +0.44 V] [Co(s)rarr Co^(3+) (aq) + 3e^(-) E^0 = - 1.81 V The standard emf of the cell reaction [3Fe(s) +2Co^(3+) (aq)rarr 3Fe^(2+) (aq) + 2Co(s)] , will be

The standard oxidation potentials, , for the half reactions are as follows : Zn rightarrow Zn^(2+) + 2e^(-) , E^(@) = +0.76V Fe rightarrow Fe^(2+)+ 2e^(-), E^(@) = + 0.41 V The EMF for the cell reaction, Fe^(2+) + Zn rightarrow Zn^(2+) + Fe