In the figure a capacitor is filled with dielectrics `K_(1)=2,K_(2)=3,K_(3)=6` and `varepsilon_(0)A/(d)=C.` The resultant capacitance between P and Q is

In the figure a capacitor is filled with dielectrics K_(1) , K_(2) and K_(3) . The resultant capacitance is

Two identical parallel plate capacitors, of capacitance C each, have plates of area A, separated by a distance d. The space between the plates of the two capacitors, is filled with three dielectrics, of equal thickness and dielectric constants K_(1),K_(2) and K_(3) . The first capacitor is filled as shown in fig. I, and the second one is filled as shown in fig. II. If these two modified capacitors are charged by the same potential V, the ratio of the energy stored in the two, would be ( E_(1) refers to capacitor (I) and E_(2) to capacitor (II)):

Two identical parallel plate capacitors, of capacitance C each, have plates of area A, separated by a distance d. The space between the plates of the two capacitors, is filled with three dielectrics, of equal thickness and dielectric constants K_(1), K_(2) and K_(3) . The first capacitor is filled as shown in fig. I, and the second one is filled as shown in fig. II. If these two modified capacitors are charged by the same potential V, the ratio of the energy stored in the two, would be ( E_(1) refers to capacitor (I) and E_(2) to capacitor (II)):

Air filled capacitor of capacitance 2 muF is filled with three dielectric material of dielectric constant K_(1) = 4, K _(2) = 4 and K_(3) = 6 as shown in the figure . The new capacitance of the capacitor is

An air capacitor of capacitance C plate area A and plate separation d has been filled with three dielectrics of constant k_(1)=3 , k_(2)=6 and k_(3)=4 as shown in figure . What is the new capacitance ?

Two identical parallel plate (air) capacitors c_(1) and c_(2) have capacitances C each. The space between their plates is now filled with dielectrics as shown. If two capacitors still have equal capacitance, obtain the relation betweenn dielectric constants k,k_(1) and k_(2) .

A parallel plate capacitor of area A, plate separation d and capacitance C is filled with four dielectric materials hving dielectric constants K_(1), K_(2), K_(3) and K_(4) as shown in the figure below. If a single dielectric material is to be used to have the same capacitance c in this capacitor, then its dielectric constant K is given by

A parallel plate capacitor with square plates is filed with four dielectrics of dielectric constants K_(1),K_(2),K_(3),K_(4), arranged as shown in the figure. The effective dielectric constant K will be :

A parallel plate capacitor is of area 6 cm^(2) and a separation 3 mm. The gap is filled with three dielectric materials of equal thickness (see figure) with dielectric constant K_(1)=10 , K_(2)=12 and K_(3) = 14 . The dielectric constant of a material which when fully inserted in above capacitor, gives same capacitance would be :

Two parallel plate capacitors, each of capacitance 40 muF, are connected is series. The space between the plates of one capacitor is filled with a dielectric material of dielectric constant K =4. Find the equivalent capacitacne of the system.