2% of aqueous urea and 6% of aqueous X are isotonic. If X is a molecular solid, calculate its molar mass

The freezing point of 4% aqueous solution of 'A' is equal to the freezing point 10% aqueous solution of 'B'. If the molecular mass of 'A' is 60, then the molecular mass of 'B' will be:

A 5% solution of cane sugar is isotonic with 0.877% solution of urea. Calculate the molecular mass of urea if the molecular mass of cane sugar is 342 .

Freezing point of a 4% aqueous solution of X is equal to freezing point of 12% aqueous is reaction of Y .if molecular weight of X is A then molecular weight of Y is :

A solution containing 10.2 g of glycrine per litre is found to be isotonic with 2% solution of glucose ("molar mass"=180 g mol^(-1)) . Calculate the molar mass of glycrine.

Active mass of a 6% solution of a compound is 2 then calculate molar mass of compound.

Freezing point of a 4% aqueous solution of X is equal to freezing point of 12% aqueous solution of Y .If molecular weight of X is A then molecular weight of Y is :

The vapour pressure of a 5% aqueous solution of a non-volatile organic substance at 373 K . Is 745 mm . Calculate the molecular mass of the solute.

For [CrCl_(3).xNH_(3)] , elevation in boiling point of the one molal solution is triple of one molal aqueous solution of urea. Assuming 100% ionisation of complex molecule, calculate the value of x.

10% solution of urea is isotonic with 6% solution of a non-volatile solute X.What is the molecular mass of solute X ?

%(w/v) of aqueous KOH solution is 1.4 What is the molarity of solution? (Molar mass of KOH= 56 )